Finding the unknown β the heart of algebraic problem-solving
An equation is like a balance scale. Whatever you do to one side, you must do to the other.
| Operation | Inverse |
|---|---|
| Addition (+) | Subtraction (β) |
| Subtraction (β) | Addition (+) |
| Multiplication (Γ) | Division (Γ·) |
| Division (Γ·) | Multiplication (Γ) |
| Squaring (Β²) | Square root (β) |
Physics: F = ma. Find acceleration when F = 50 N, m = 10 kg.
50 = 10Β·a
50/10 = a β Divide both sides by 10
a = 5 m/sΒ²
Physics: v_f = v_i + at. Find time when v_f = 20 m/s, v_i = 5 m/s, a = 3 m/sΒ².
20 = 5 + 3t
20 - 5 = 3t β Subtract 5 from both sides
15 = 3t
15/3 = t β Divide both sides by 3
t = 5 s
Physics: Two objects with momenta pβ = mv and pβ = 2mv collide. Find v if total p = 30 kgΒ·m/s and m = 2 kg.
mv + 2mv = 30
3mv = 30 β Combine like terms
3(2)v = 30 β Substitute m = 2
6v = 30
v = 5 m/s
Physics: 1/f = 1/do + 1/di (thin lens equation). Find di when f = 10 cm, do = 15 cm.
1/10 = 1/15 + 1/di
Multiply everything by 30 (LCM of 10, 15):
3 = 2 + 30/di
3 - 2 = 30/di
1 = 30/di
di = 30 cm
1) a = 15 m/sΒ² 2) t = 5 s 3) x = 20 m 4) m = 5 kg 5) v = β80 = 8.94 m/s
6) t = β40 = 6.32 s 7) x = 8 8) v = 10 9) v = 10 m/s 10) a = 0 (forces cancel)