Amplitude, period, phase shift — the language of waves and oscillations
| Parameter | Name | Physics Meaning | Effect on Graph |
|---|---|---|---|
| A | Amplitude | Max displacement | Vertical stretch by |A| |
| ω | Angular frequency | Rad/s (oscillations) | Period = 2π/ω |
| φ | Phase shift | Initial phase | Horizontal shift by -φ/ω |
| D | Vertical shift | Equilibrium position | Shift up/down by D |
cos θ = sin(θ + π/2) — cosine is sine shifted left by 90° (π/2).
In physics, choose based on initial conditions:
y(x,t) = 0.02 sin(4πx - 20πt) (SI units)
Standard form: y = A sin(kx - ωt)
A = 0.02 m = 2 cm (amplitude)
k = 4π rad/m → λ = 2π/k = 2π/(4π) = 0.5 m
ω = 20π rad/s → f = ω/2π = 10 Hz, T = 0.1 s
v = fλ = 10 × 0.5 = 5 m/s
Mass on spring: x = 0.1 cos(5t) (meters, seconds)
x = 0.1 cos(5t)
v = dx/dt = -0.1(5) sin(5t) = -0.5 sin(5t)
a = dv/dt = -0.5(5) cos(5t) = -2.5 cos(5t) = -ω²x
A = 0.1 m, ω = 5 rad/s
v_max = Aω = 0.5 m/s
a_max = Aω² = 2.5 m/s²
T = 2π/5 ≈ 1.26 s
At t=0, x=0.05m, v=0.3m/s positive. ω=4 rad/s. Find A, φ for x = A sin(ωt + φ).
x(0) = A sin φ = 0.05
v(0) = Aω cos φ = 0.3 → A(4) cos φ = 0.3 → A cos φ = 0.075
Divide: tan φ = 0.05/0.075 = 2/3 → φ = tan⁻¹(2/3) ≈ 0.588 rad
A = 0.05/sin φ ≈ 0.090 m
x = 0.090 sin(4t + 0.588)
1) A=3, ω=2, T=π, f=1/π 2) A=2, λ=2, shift=1/3 right 3) y=0.01 sin(5πx) or cos
4) x_max=0.2, v_max=2, a_max=20, T=0.2π 5) sin (starts at 0, going +) 6) A=√2, phase=π/4